1. Tardigrade
  2. Question
  3. Chemistry
  4. The volume (in mL) of 0.1 M AgNO3 required for complete precipitation of chloride ions present in 30 mL of 0.01 M solution of [Cr(H2O)5Cl]Cl2, as silver chloride is close to

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The volume (in mL) of $0.1\, M\, AgNO_3$ required for complete precipitation of chloride ions present in $30 \,mL$ of $0.01\, M$ solution of $[Cr(H_2O)_5Cl]Cl_2$, as silver chloride is close to

Some Basic Concepts of Chemistry

Solution:

$[Cr(H_2O)_5Cl]Cl_2 + 2AgNO_3 \to$
$2AgCl + [Cr(H_2O)_5Cl](NO_3)_2$
Number of ionisable chloride ions in complex
$[Cr(H_2O)_5Cl]$ $Cl_2 = 2$
Millimoles = Molarity $\times$ Volume $(mL) \times 2$
$ = 0.01 \times 30 \times 2 = 0.6$
Therefore, required $Ag^+ = 0.6$ millimoles
Millimoles = Molarity $\times V$ (in mL)
$0.6 = 0.1 \times V; V= 6\,mL$