Question

The volume charge density as a function of distance $x$ from one face inside a unit cube is varying as shown in the figure. The total flux (in $SI $ units) through the cube is

Answer 1

$\phi=\frac{Q_{\text {in }}}{\varepsilon_{0}}=\int \frac{\rho d V}{\varepsilon_{0}}$
$=\frac{\text { Area under } \rho v / s x \text { graph }}{\varepsilon_{0}}=\frac{3}{4}$