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Q. The Vividh Bharati station of All India Radio, Delhi, broadcasts on a frequency of $1,368\, kHz$ (kilo hertz). The wavelength of the electromagnetic radiation is

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Solution:

$\lambda = \frac{c}{\upsilon} =\frac{ 3.00 \times10^{8} ms^{-1}}{1368 kHz} $
$ = \frac{3.0\times10^{8} ms^{-1}}{1368 \times10^{3}s^{-1}}$
$ = 219.3 m$