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Physics
The vertical component of velocity of a projectile at its maximum height (u = velocity of projection, θ = angle of projection) is
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Q. The vertical component of velocity of a projectile at its maximum height ($u =$ velocity of projection, $\theta =$ angle of projection) is
KEAM
KEAM 2014
Motion in a Plane
A
$u \sin \theta$
B
$u \cos \theta$
C
$\frac{u}{\sin \theta}$
D
0
E
$\frac{u}{\cos \theta}$
Solution:
The vertical component of velocity of a projectile at maximum height is zero.