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  4. The vertical component of earth's magnetic field at a place is √3 times the horizontal component the value of angle of dip at this place is

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Q. The vertical component of earth's magnetic field at a place is $\sqrt{3}$ times the horizontal component the value of angle of dip at this place is

Magnetism and Matter

Solution:

As, $B_{V} = \sqrt{3}\,B_{H}$
Also, $tan\,\delta = \frac{B_{V}}{B_{H}} = \frac{\sqrt{3}B_{H}}{B_{H}} = \sqrt{3}$ or $\delta = tan^{-1} \, \left(\sqrt{3}\right) = 60^{\circ}$
$\therefore \quad$ Angle of dip, $\delta = 60^{\circ}$.