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Q. The vertex of the parabola $(x-4)^{2}+2 y=9$ is :

Conic Sections

Solution:

The given parabola can be written as:
$(x-4)^{2}=-2(y-9 / 2)$
which is of the form $x^{2}=4$ ay
Thus, the vertex is $(4,9 / 2)$.