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  4. The vernier constant of Vernier callipers is 0.1 mm and it has zero error of (-0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be × 10-2 cm.

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Q. The vernier constant of Vernier callipers is $0.1\, mm$ and it has zero error of $(-0.05) cm$. While measuring diameter of a sphere, the main scale reading is $1.7\, cm$ and coinciding vernier division is $5$. The corrected diameter will be_____ $\times 10^{-2} cm$.

JEE MainJEE Main 2022Physical World, Units and Measurements

Solution:

Measured diameter $= MSR + VSR \times VC$
$=1.7+0.01 \times 5$
$=1.75$
Corrected $=$ Measured $-$ Error
$=1.75-(-0.05)$
$=1.80\, cm$
$=180 \times 10^{-2} cm$
$180$