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Q.
The velocity versus time curve of a moving point is as given below. The maximum acceleration and displacement are respectively
Motion in a Straight Line
Solution:
The maximum acceleration will occur in the duration $30\, s$ to $40\, s$. So
$a =\frac{ v _{2}- v _{1}}{ t _{2}- t _{1}}=\frac{60-20}{40-30}=4\, cm / \sec ^{2}$
