Thank you for reporting, we will resolve it shortly
Q.
The velocity-time graph of a body is given in figure. The maximum acceleration in $m s ^{-2}$ is
Motion in a Straight Line
Solution:
Maximum acceleration will be from $30$ to $40\, s$, because slope in this interval is maximum.
$a=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}$
$=\frac{60-20}{40-30}=4\, ms ^{-2}$
