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Q.
The variation of potential energy of harmonic oscillator is as shown in figure. The spring constant is
Oscillations
Solution:
Total potential energy $=0.04\, J$
Resting potential energy $=0.01 \,J$
Maximum kinetic energy $=(0.04-0.01)$
$=0.03\,J =\frac{1}{2} m \omega^{2} a^{2}=\frac{1}{2} k a^{2}$
$0.03=\frac{1}{2} \times k \times\left(\frac{20}{1000}\right)^{2}$
$k=0.06 \times 2500\, N / m =150 \,N / m$
