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  4. The vapour pressure of water at 23° C is i9.8 mm of Hg.0.1 mol of glucose is dissolved in 178.2 g of water. What is the vapour pressure (in mm Hg) of the resultant solution?

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Q. The vapour pressure of water at $ 23{}^\circ C $ is i9.8 mm of Hg.0.1 mol of glucose is dissolved in 178.2 g of water. What is the vapour pressure (in mm Hg) of the resultant solution?

JamiaJamia 2011

Solution:

Moles of glucose; $ n{{C}_{6}}{{H}_{12}}{{O}_{6}}=0.1 $ Moles of water; $ {{n}_{{{H}_{2}}O}}=\frac{178.2}{18}=9.9 $ Mole fraction of water, $ {{x}_{{{H}_{2}}O}}=\frac{9.9}{9.9+0.1}=0.99 $ $ {{P}_{solution}}={{P}_{solvent}}\times {{x}_{solvent}} $ $ =19.8\times 0.99 $ $ =19.602mm\text{ }Hg $