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  4. The vapour pressure of water at 20° is 17.5 mm Hg If 18 g of glucose (C6H12O6) is added to 178.2 g of water at 20°C, the vapour pressure of the resulting solution will be:

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Q. The vapour pressure of water at $20^{\circ}$ is $17.5 \,mm\,Hg$ If $18 g$ of glucose $(C_{6}H_{12}O_{6})$ is added to $178.2\,g$ of water at $20^{\circ}C$, the vapour pressure of the resulting solution will be:

Solutions

Solution:

$\frac{P^{\circ}-P_{s}}{P_{s}}=\frac{w \times M}{m \times W} $
$\frac{17.5-P_{S}}{P_{S}}=\frac{18\times18}{180\times178.2}$
$\frac{17.5-P_{S}}{P_{S}}=0.01$
$P_{S}=17.325\, mmHg$