1. Tardigrade
  2. Question
  3. Chemistry
  4. The vapour pressure of the solution is comparatively smaller than that of the pure solvent (Raoult's law). Consequently, the temperature at which the vapour pressure of solution becomes equal to the external pressure, will be greater than that of pure solvent, rising its boiling point. Since, the decrease in vapour pressure is directly proportional to the amount fraction of the solute in the solution, it is therefore expected that the corresponding increase in the boiling points also depends on the amount fraction of the solute in the solution When a non-volatile solute is dissolved in a solvent, the relative lowering of vapour pressure is equal to

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Q. The vapour pressure of the solution is comparatively smaller than that of the pure solvent (Raoult's law). Consequently, the temperature at which the vapour pressure of solution becomes equal to the external pressure, will be greater than that of pure solvent, rising its boiling point. Since, the decrease in vapour pressure is directly proportional to the amount fraction of the solute in the solution, it is therefore expected that the corresponding increase in the boiling points also depends on the amount fraction of the solute in the solution
When a non-volatile solute is dissolved in a solvent, the relative lowering of vapour pressure is equal to

Solutions

Solution:

The relative lowering of vapour pressure is equal to the mole fraction of solute