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  4. The vapour pressure of pure water at 26° C is 25.21 torr. What is the vapour pressure of a solution which contains 20.0 g glucose, C6H12O6 in 70 g water?

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Q. The vapour pressure of pure water at $ 26{}^\circ C $ is 25.21 torr. What is the vapour pressure of a solution which contains 20.0 g glucose, $ {{C}_{6}}{{H}_{12}}{{O}_{6}} $ in 70 g water?

CMC MedicalCMC Medical 2011

Solution:

Moles of glucose $ =\frac{20.0\,g\,glu\cos e}{180\,g\text{/}mol}=0.111\,\,mol $ Moles of water $ =\frac{70.0\,g\,{{H}_{2}}O}{18.0g/mol}=3.89\,mol\,{{H}_{2}}O $ $ x({{H}_{2}}O)=\frac{3.89}{0.11+3.89}=0.972 $ $ p=p{}^\circ {{x}_{{{H}_{2}}O}}=(25.21\,\,\text{torr})\,(0.972)=24.5\,\,\text{torr} $