1. Tardigrade
  2. Question
  3. Chemistry
  4. The vapour pressure of pure liquid textA is text10 texttorr and at the same temperature when text9 textg of textB solid dissolved in text20 textg of textA, its Vapour pressure is reduced to text5 texttorr text. If the molecular mass of textA is text200 textamu, then the molecular mass of textB is

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Q. The vapour pressure of pure liquid $\text{A}$ is $\text{10} \, \text{torr}$ and at the same temperature when $\text{9} \, \text{g}$ of $\text{B}$ solid dissolved in $\text{20} \, \text{g}$ of $\text{A,}$ its Vapour pressure is reduced to $\text{5} \, \text{torr} \text{.}$ If the molecular mass of $\text{A}$ is $\text{200} \, \text{amu,}$ then the molecular mass of $\text{B}$ is

NTA AbhyasNTA Abhyas 2020Solutions

Solution:

$\frac{P^{0} - P_{s}}{P_{s}}=\frac{n}{N}$

$\frac{10 - 5}{5}=\frac{9 \times 200}{M \times 20}$

$\text{M} \, \text{=} \, \text{90} \, \text{amu}$