1. Tardigrade
  2. Question
  3. Chemistry
  4. The vapour pressure of pure liquid A is 10 torr and at the same temperature when 1 g of B solid is dissolved in 20 g of A, its vapour pressure is reduced to 9.0 torr. If the molecular mass of A is 200 amu, then the molecular mass of B is

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Q. The vapour pressure of pure liquid A is 10 torr and at the same temperature when 1 g of B solid is dissolved in 20 g of A, its vapour pressure is reduced to 9.0 torr. If the molecular mass of A is 200 amu, then the molecular mass of B is

Solutions

Solution:

$\frac{10-9}{10}=\frac{\frac{1}{x}}{\frac{1}{x}+\frac{20}{200}}$
$\frac{1}{10}=\frac{\frac{1}{x}}{\frac{1}{x}+\frac{1}{10}}=\frac{10}{x+10}$
$\Rightarrow x=90$