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Chemistry
The vapour pressure of pure benzene at 25° C is 640 mm Hg and that of the solute A in benzene is 630 mm of Hg. The molality of solution is
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Q. The vapour pressure of pure benzene at $25^\circ C$ is 640 mm Hg and that of the solute A in benzene is 630 mm of Hg. The molality of solution is
NTA Abhyas
NTA Abhyas 2020
Solutions
A
0.2 m
16%
B
0.4 m
26%
C
0.5 m
27%
D
0.1 m
31%
Solution:
$\text{P} \, \text{=} \, \text{P}^{\text{o}} \text{X}_{\text{A}}$
$630=640X_{A}$
$X_{A}=\frac{630}{640}=0.984$
$X_{B}=0.016$
$m=\frac{X_{B} \times 1000}{X_{A} M_{A}}=\frac{0.016 \times 1000}{0.984 \times 78}$
$=0.2 \,m$