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  4. The vapour pressure of pure Benzene and Toluene are 900 torr and 600 torr respectively at 300K . A liquid solution is formed by mixing 1 mole each of benzene and toluene. If the pressure over the solution is reduced slowly under isothermal condition then mole fraction of benzene in the residue liquid, which has normal boiling point at 300K is:-

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Q. The vapour pressure of pure Benzene and Toluene are $900$ torr and $600$ torr respectively at $300K$ . A liquid solution is formed by mixing $1$ mole each of benzene and toluene. If the pressure over the solution is reduced slowly under isothermal condition then mole fraction of benzene in the residue liquid, which has normal boiling point at $300K$ is:-

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Solution:

For residue solution at its normal boiling point:
$P_{s}=1atm=760$ torr
$P_{s}=X_{b}\times 900+X_{1}\times 600$
$760=900X_{b}+\left(1 - X_{b}\right)\times 600=600+300X_{b}$
$X_{b}=\frac{160}{300}=0.53$