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Q. The vapour pressure of pure benzene and toluene are $160$ and $60$ torr respectively. The mole fraction of toluene in vapour phase in contact with equimolar solution of benzene and toluene is

Solutions

Solution:

For equimolar solution, let us take

$x_{A}=x_{B}=0.5$

$P_{\text {benzene }}=160 \times 0.5=80 $ torr,

$P_{\text {toluene }}=60 \times 0.5=30$ torr

$P_{\text {total }}=80+30=110 $ torr

Mole fraction of toluene in vapour phase

$=\frac{\text { Partial vapour pressure of toluene }}{\text { Total vapour pressure }}$

$=\frac{30}{110}=0.27$