1. Tardigrade
  2. Question
  3. Chemistry
  4. The vapour pressure of benzene and pure toluene at 70°C are 500 mm and 200 mm Hg respectively.If they form an ideal solution what is the mole fraction of benzene in a mixture boiling at 70° C at a total pressure of 380 mm Hg ?

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Q. The vapour pressure of benzene and pure toluene at 70$^\circ$C are 500 mm and 200 mm Hg respectively.If they form an ideal solution what is the mole fraction of benzene in a mixture boiling at 70$^\circ$ C at a total pressure of 380 mm Hg ?

Solutions

Solution:

Let mol. fraction of Benzene is $x$
$\therefore $ 380 = $x \times 500 + (1 - x ) 200 $ or $x$ = 0.6.