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  4. The vapour density of PCl5 at 300° C is 60. Its dissociation percentage will be at this temperature

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Q. The vapour density of $ PC{{l}_{5}} $ at $ 300{}^\circ C $ is 60. Its dissociation percentage will be at this temperature

Rajasthan PETRajasthan PET 2004

Solution:

Normal molecular weight of $ PC{{l}_{5}}=2\times $ vapour density $ =2\times 60 $ $ =120 $ Observed molecular weight of $ PC{{l}_{5}}=31+(35.5)\times 5 $ $ =31+177.5 $ $ =208.5 $ van-t Hoff factor $ (i)=\frac{208.5}{120} $ $ =1.7375=1.73 $ Degree of dissociation $ =\frac{i-1}{n-1} $ $ =\frac{1.73-1}{2-1} $ $ =0.73 $ % dissociation $ =0.73\times 100=73% $