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Q. The van’t Hoff factor $i$ for an infinitely dilute solution of $NaHSO_{4}$ is:

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Solution:

If the solution is infinitely dilute, $NaHSO_{4}$ would dissociate completely
$\therefore NaHSO_{4} \to Na^{+}+HSO^{-}_{4}$
$HSO^{-}_{4}$ would further dissociate as:
$HSO^{-}_{4} \to H^{+} +SO^{-}_{4}$
$i = 3$