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  4. The van’t Hoff factor for 0.1 M Ba(NO3)2 solution is 2.74. The degree of dissociation is

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Q. The van’t Hoff factor for $0.1\, M\, Ba(NO_3)_2$ solution is 2.74. The degree of dissociation is

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Solution:

$\alpha = \frac{i-1}{n-1} = \frac{2.74-1}{3-1} = 0.87 = 87\%$