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Chemistry
The values of the crystal field stabilization energies for a high spin d 6 metal ion in octahedral and tetrahedral fields, respectively, are:
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Q. The values of the crystal field stabilization energies for a high spin d $^{6}$ metal ion in octahedral and tetrahedral fields, respectively, are:
JEE Main
JEE Main 2020
Coordination Compounds
A
$-0.4 \Delta_{0}$ and $-0.27 \Delta_{ t }$
8%
B
$-1.6 \Delta_{0}$ and $-0.4 \Delta_{t}$
10%
C
$-0.4 \Delta_{0}$ and $-0.6 \Delta_{ t }$
69%
D
$-2.4 \Delta_{0}$ and $-0.6 \Delta_{ t }$
13%
Solution:
For high spin octahedral field
$CFSE =(4)\left(-0.4 \Delta_{0}\right)+2\left(0.6 \Delta_{0}\right)=-0.4\, \Delta_{0}$
For high spin tetrahedral field
$CFSE =3\left(-0.6 \Delta_{ t }\right)+3\left(0.4 \Delta_{ t }\right)=-0.6 \Delta_{ t }$