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  4. The values of observed and calculated molecular weights of silver nitrate are 92.64 and 170 respectively. The degree of dissociation of silver nitrate will be

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Q. The values of observed and calculated molecular weights of silver nitrate are 92.64 and 170 respectively. The degree of dissociation of silver nitrate will be

Solutions

Solution:

$i=\frac{\text { Normal mol. mass }}{\text { Observed mol. mass }}$

$=\frac{170}{92.64}=1.835$

$\alpha=\frac{i-1}{n-1} ;$ where, $n=2$ for $AgNO _{3}$

$\alpha=\frac{1.835-1}{2-1}$

$=0.835=83.5 \%$