1. Tardigrade
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  4. The values of four quantum numbers of valence electron of an element are n=4,l=0,m=0 and s=+(1/2). The element is:

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Q. The values of four quantum numbers of valence electron of an element are $ n=4,l=0,m=0 $ and $ s=+\frac{1}{2}. $ The element is:

EAMCETEAMCET 2004

Solution:

Four quantum numbers are $ n=4 $ $ l=0 $ $ m=0 $ $ s=+\frac{1}{2} $ $ n=4 $ indicates that the valence electron present in 4th shell (4th period) $ l=0 $ indicates that the valence electron is present in s-subshell. indicates that the valence electron is present in orbital of s-subshell. $ s=+\frac{1}{2} $ indicates that the spining of electron in orbital is clockwise. So, from the above discussion it is clear that valence electron is present in 4^ subshell as $ 4{{s}^{1}}.{{s}^{1}} $ indicates that the element is present in IA group. So, the element present in 4th period and IA group is potassium (K).