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Q. The value of $X$ for an aldoheptose, when $X$ is
$X =\frac{\text { No. of stereoisomers }}{8}$

Biomolecules

Solution:

No. of chiral center in an aldoheptoses
image
when terminal groups are different.
No. of isomers $=2^{5}=32$
$X=\frac{32}{8}=4$