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Q. The value of $X$ for a $2$ -ketoheptose, when $X$ is
$X =\frac{\text { No. of stereoisomers }}{8}$

Biomolecules

Solution:

No. of chiral center in $2$ -ketoheptose $=4$.
No. of isomers (when terminal groups are different) $=2^{4}=16$
$X=\frac{16}{8}=2$