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  4. The value of wavelength radiation emitted due to transition of electrons from n = 4 to n - 1 state in hydrogen atom will be

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Q. The value of wavelength radiation emitted due to transition of electrons from $n$ = 4 to $n$ - 1 state in hydrogen atom will be

Atoms

Solution:

We know that, $\frac{1}{\lambda}= RZ ^{2}\left(\frac{1}{ n _{1}^{2}}-\frac{1}{ n _{2}^{2}}\right)$
For hydrogen atom, atomic no. $Z=1$
So, $\frac{1}{\lambda}= R \left(\frac{1}{2}^{2}-\frac{1}{4}^{2}\right)=\frac{3 R }{16}$
$
\Rightarrow \lambda=\frac{16}{3 R}
$