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  4. The value of Van't Hoff factor (i) for K 3[ Fe ( CN ] is X, if it undergoes 75 % dissociation in aqueous medium, calculate 4 X ?

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Q. The value of Van't Hoff factor (i) for $K _{3}[ Fe ( CN ]$ is $X$, if it undergoes $75 \%$ dissociation in aqueous medium, calculate $4 X$ ?

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$i=\frac{C - Cα + 3 Cα + Cα}{C}=1+3\alpha $
Given $\alpha =0.75$
$\therefore i=1+3\times 0.75=3.254X=4\times 3.25=13$