Q. The value of the 'spin only' magnetic moment for one of the following configurations is $2.84 \,BM$. The correct one is
Coordination Compounds
Solution:
Spin only magnetic moment $=\sqrt{ n ( n +2)}$ B.M.
Where, $n =$ no. of unpaired electrons.
Given, $\sqrt{n(n+2)}=2.84$
or, $n(n+2)=8.0656$
or, $n =2$
In an octahedral complex, for a $d^{4}$ configuration in a strong filed ligand, number of unpaired electrons $=2$
