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Q. The value of the $\sin \; 1^{\circ} + \sin \; 2^{\circ} +......+ \sin 359^{\circ}$ is equal to

KCETKCET 2016Trigonometric Functions

Solution:

$ \sin 1^{\circ}+\sin 2^{\circ}+\sin 3^{\circ}+\ldots+\sin 359^{\circ} $
$=\left(\sin 1^{\circ}+\sin 359^{\circ}\right)+\left(\sin 2^{\circ}+\sin 358^{\circ}\right)+\ldots +\sin 180^{\circ} $
$=0+0+0+\ldots+0=0$
$ \left[\because \sin \theta+\sin \left(360^{\circ}-\theta\right)=0\right] $