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Q.
The value of $\tan \, 3A- \tan \, 2A- \tan \, A$ is:
Trigonometric Functions
Solution:
We have,
3A = 2A+ A $\Rightarrow $ tan3A = tan(2A + A)
$ = \frac{\left(\tan2 A + \tan A\right)}{\left(1- \tan2 A \tan A\right)} $
$ \Rightarrow \, $ tan 3 A - tan 3 A tan 2 A tan A = tan 2 A + tan A
$\Rightarrow \, $ tan 3 A - tan 2 A - tan A = tan 3 A tan 2 A tan A