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Q. The value of $\tan ^2\left(\sec ^{-1} 2\right)+\cot ^2\left(\operatorname{cosec}^{-1} 3\right)$ is equal to

Inverse Trigonometric Functions

Solution:

$\Theta \tan ^2 \theta=\sec ^2 \theta-1 \text { and } \cot ^2 \theta=\operatorname{cosec}^2 \theta-1$
$\therefore \text { Given expression }=\sec ^2\left(\sec ^{-1} 2\right)-1+\operatorname{cosec}^2\left(\operatorname{cosec}^{-1} 3\right)-1 $
$=4-1+9-1=11 $