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Q. The value of $\sin (\cot^{-1}x)$ is

Inverse Trigonometric Functions

Solution:

Put $cot^{-1} x=A $
$ \therefore x=cot\,A $
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$ \therefore sin\,A = \frac{1}{\sqrt{x^{2}+1}} = \left(1+x^{2}\right)^{-{1}/{2}}$