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  4. The value of sec (2π/3)+cosec (5π/6) is equal to

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Q. The value of $sec \frac{2\pi}{3}+cosec \frac{5\pi}{6}$ is equal to

Trigonometric Functions

Solution:

$sec \frac{2\pi}{3}+cosec \frac{5\pi}{6}$
$=sec\left(\pi -\frac{\pi}{3}\right)+cosec\left(\pi-\frac{\pi}{6}\right)$
$=-sec \frac{\pi}{3}+cosec \frac{\pi}{6}$
$=-2+2=0$