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Q. The value of magnetic quantum number of the last electron of " $ Na $ " is

J & K CETJ & K CET 2018Atoms

Solution:

Electronic configuration of $Na$ is $1s^{2}2s^{2}2p^{6}3s^{1}$ . Here the valence electron is in $3\,s$ orbital.
The $l$ value of this orbital is zero So, the magnetic quantum number of this orbital is zero