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Q. The value of $\log _{80} 8$ lies between. ____

Logarithm

Solution:

$\log _{160} 8$
Now, $8^2=64,8^3=512$
And, $64< 160< 512 $
$\Rightarrow 8^2< 160< 8^3$
$\therefore$ The value of $\log _{160} 8$ lies between $\frac{1}{3}$ and $\frac{1}{2}$.