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Q. The value of |log5729log35log527log925|×|log35log275log59log59| is

AP EAMCETAP EAMCET 2020

Solution:

|log5729log35log527log925|×|log35log275log59log59|
=|6log53log353log53log35|×|log3513log352log532log53|
=3log53log35|2111|×2log35log53|11/311|
=6[21]×[113]=4
Hence the options
log35×log581=(log35)×(4log53)=4