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Q. The value of $\displaystyle\lim_{x\to0} \frac{\left|x\right|}{x} $ is

KCETKCET 2018Limits and Derivatives

Solution:

$LHL =\displaystyle\lim _{ h \rightarrow 0} f (0- h )=\displaystyle\lim _{ h \rightarrow 0} \frac{|0- h |}{0- h }=\displaystyle\lim _{ h \rightarrow 0} \frac{ h }{- h }=\displaystyle\lim _{ h \rightarrow 0}(-1)=-1$
$RHL =\displaystyle\lim _{ x \rightarrow 0} f (0+ h )=\displaystyle\lim _{ h \rightarrow 0} \frac{|0+ h |}{0+ h }=\displaystyle\lim _{ h \rightarrow 0} \frac{ h }{ h }=\displaystyle\lim _{ h \rightarrow 0}(1)=1$
$\therefore \,LHL \neq RHL$
$ \Rightarrow \,\displaystyle\lim _{x \rightarrow 0} \frac{| x |}{ x }$ does not exist