Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The value of x2dxx6+a6 is equal to

KCETKCET 2021Integrals

Solution:

x3=t3x2dx=dt
I=131t2+(a3)2dt
=13log[t+t2+a6]
=13log[x3+x6+a6]+c