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Q. The value of $ \int_{{}}^{{}}{\frac{{{\sin }^{2}}x{{\cos }^{2}}x}{{{({{\sin }^{3}}x+{{\cos }^{3}}x)}^{2}}}dx} $ is

Bihar CECEBihar CECE 2015

Solution:

Let $ I=\int_{{}}^{{}}{\frac{{{\sin }^{2}}x{{\cos }^{2}}x}{{{({{\sin }^{3}}x+{{\cos }^{3}}x)}^{2}}}}dx $ $ \int_{{}}^{{}}{\frac{{{\tan }^{2}}x{{\sec }^{2}}x}{{{(1+{{\tan }^{3}}x)}^{2}}}dx} $ [dividing numerator and denominator by $ {{\cos }^{6}}x $ ] $ =\frac{1}{3}\int_{{}}^{{}}{\frac{3{{\tan }^{2}}x{{\sec }^{2}}x}{{{(1+{{\tan }^{3}}x)}^{2}}}}dx $ $ =\frac{1}{3}\int_{{}}^{{}}{\frac{1}{{{(1+{{\tan }^{3}}x)}^{2}}}}d(1+{{\tan }^{3}}x) $ $ =-\frac{1}{3(1+{{\tan }^{2}}x)}+C $