1. Tardigrade
  2. Question
  3. Chemistry
  4. The value of Henry’s law constant for some gases at 293 K is given below. Arrange the gases in the increasing order of their solubility. He: 144.97 kbar, H2: 69.16 kbar, N2: 76.48 kbar, O2: 34.86 kbar

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Q. The value of Henry’s law constant for some gases at $293\, K$ is given below. Arrange the gases in the increasing order of their solubility.
$He : 144.97\, kbar$, $H_2 : 69.16\, kbar$,
$N_2 : 76.48 \,kbar$, $O_2 : 34.86\, kbar$

Solutions

Solution:

$
K _{ H }=\frac{ p }{ x }
$
At constant pressure, $K _{ H }$ is inversely proportional to $x$. Therefore, the higher the $K _{ H }$ lower the solubility.
The increasing solubility order is:
$He < N _{2}< H _{2}< O _{2}$