Question

The value of $ {{\varepsilon }_{0}} $ will be

• A. $ 8.85\,\times \,{{10}^{-12}}{{C}^{2}}/N-{{m}^{2}} $
• B. $ 8.85\,\times \,{{10}^{-12}}\,Fermi $
• C. $ 9\,\times \,{{10}^{-13}}\,{{C}^{2}}/N-{{m}^{2}} $
• D. $ 9\,\times \,{{10}^{-13}}\,Fermi $

Answer 1

Answer: (A)

$ \frac{1}{4\pi {{\varepsilon }_{0}}}=9\times {{10}^{9}}N{{m}^{2}}/C $
$ \therefore $ $ {{\varepsilon }_{0}}=\frac{1}{9\times {{10}^{9}}\times 4\pi }{{C}^{2}}/N-{{m}^{2}} $
$ =8.85\times {{10}^{-12}}{{C}^{2}}/N-{{m}^{2}} $