Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
The value of electric permittivity of free space is
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. The value of electric permittivity of free space is
Punjab PMET
Punjab PMET 2011
Electric Charges and Fields
A
$9 \times 10^{9} NC ^{2} / m ^{2}$
21%
B
$8.9 \times 10^{-12} Nm ^{2} / C ^{2} s$
22%
C
$8.9 \times 10^{-12} C ^{2} / Nm ^{2}$
31%
D
$9 \times 10^{9} C ^{2} / Nm ^{2}$
26%
Solution:
Electric permittivity of free space
$\varepsilon_{0} =8.85 \times 10^{-12} C ^{2} / N - m ^{2}$
$=8.9 \times 10^{-12} C ^{2} / N - m ^{2}$