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Q. The value of current in the given circuit if the ammeter is a galvanometer with a resistance $R_{G}=50\, \Omega$ is
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Moving Charges and Magnetism

Solution:

$I=\frac{V}{R_{e w}}$
$R _{ eq }= R _{ g }+3=50+3$
$=53 \,\Omega$
$I=\frac{V}{R_{e q}}=\frac{5}{53}=0.094 \,A$