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  4. The value of cot ( cot -1(-1)+ cot -1(-2)+ cot -1(-3)) equals

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Q. The value of $\cot \left(\cot ^{-1}(-1)+\cot ^{-1}(-2)+\cot ^{-1}(-3)\right)$ equals

Inverse Trigonometric Functions

Solution:

$\cot \left(\cot ^{-1}(-1)+\cot ^{-1}(-2)+\cot ^{-1}(-3)\right)=\cot \left(3 \pi-\frac{\pi}{2}\right)=\cot \frac{5 \pi}{2}=0$