Thank you for reporting, we will resolve it shortly
Q.
The value of $\frac{cos 68^{o}}{sin 56^{o} \cdot sin 34^{o} \cdot tan 22^{o}}$ is equal to
NTA AbhyasNTA Abhyas 2022
Solution:
$\frac{cos 68^{o} \cdot cos 22^{o}}{sin 56^{o} \cdot sin 34^{o} \cdot sin 22^{o}}$
$sin34^{o}=cos56^{o}$ and $sin22^{o}=cos68^{o}$
$=\frac{2 cos 22^{o}}{2 sin 34^{o} \cdot cos 34^{o}}=\frac{2 cos 22^{o}}{sin 68^{o}}=2$