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Q. The value of $\cos 22 \frac{1^{\circ}}{2}$ is

Trigonometric Functions

Solution:

We have,
$\cos \frac{A}{2} = \pm \sqrt{ \frac{1 + \cos A}{2}}$
Putting $A = 45^{\circ}$ , we get
$\cos 22 \frac{1^{\circ}}{2} = \sqrt{\frac{1 + \cos 45^{\circ}}{2}}$
$\left[ \because \cos22 \frac{1^{\circ}}{2} is + ve \right] $
$\Rightarrow \cos22 \frac{1^{\circ}}{2} = \sqrt{\frac{1+1/\sqrt{2}}{2}} = \sqrt{\frac{\sqrt{2} + 1}{2\sqrt{2}} }$