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Q. The value of $\cos 0+\cos \frac{\pi}{9}+\cos \frac{2 \pi}{9}+\cos \frac{3 \pi}{9}+\cos \frac{4 \pi}{9}+\cos \frac{5 \pi}{9}+\cos \frac{6 \pi}{9}+\cos \frac{7 \pi}{9}+\cos \frac{8 \pi}{9}$ is

Trigonometric Functions

Solution:

$1+\cos \frac{\pi}{9}+\cos \frac{2 \pi}{9}+\cos \frac{3 \pi}{9}+\cos \frac{4 \pi}{9}-\cos \frac{4 \pi}{9}-\cos \frac{3 \pi}{9}-\cos \frac{2 \pi}{9}-\cos \frac{\pi}{9}=1$